描述:nums1 中数字 x 的「下一个更大元素」是指 x 在 nums2 中对应位置右侧的第一个比 x 大的元素。给你两个没有重复元素的数组 nums1 和 nums2,其中 nums1 是 nums2 的子集。对于每个 nums1[i],找出其在 nums2 中的下一个更大元素;若不存在,返回 -1。
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const posToTime = new Map(); // 映射:位置 → 到达终点的时间,详情可参考heLLoword翻译官方下载
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